1999 TOYOTA CAMRY steering

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Page 3568 of 4592

TOYOTA CAMRY 1999  Service Repair Manual SA07D±01
R08859
SST
R00789
SST
W02110
SST
R11486
SST
SST
SA±12
± SUSPENSION AND AXLEFRONT AXLE  HUB
1963 Author: Date:
DISASSEMBLY
1. REMOVE DUST DEFLECTOR
Using a screwdriver, remove the dust de

Page 3569 of 4592

TOYOTA CAMRY 1999  Service Repair Manual SA07E±01
R00792
SST
R08860
SST
SST
Z19236
SST
SST
± SUSPENSION AND AXLEFRONT AXLE  HUB
SA±13
1964 Author: Date:
REASSEMBLY
1. INSTALL BEARING
(a) Using SST and a press, install a new bearing to t

Page 3573 of 4592

TOYOTA CAMRY 1999  Service Repair Manual SA08Q±01
FA1535
SST
W03093
W03142
± SUSPENSION AND AXLEFRONT DRIVE SHAFT (5S±FE)
SA±17
1968 Author: Date:
REMOVAL
NOTICE:
The hub bearing could be damaged if it is subjected to the
vehicle  weig

Page 3590 of 4592

TOYOTA CAMRY 1999  Service Repair Manual SA07N±01
Z19346
To Outside SA±34
± SUSPENSION AND AXLEFRONT SHOCK ABSORBER
1985 Author: Date:
REMOVAL
1. REMOVE FRONT WHEEL
Torque: 103 N´m (1,050 kgf´cm, 76 ft´lbf)
2. REMOVE FLEXIBLE HOSE AN

Page 3600 of 4592

TOYOTA CAMRY 1999  Service Repair Manual SA07Y±01
R08859
SST SA±44
± SUSPENSION AND AXLEFRONT LOWER BALL JOINT
1995 Author: Date:
REMOVAL
1. REMOVE STEERING KNUCKLE WITH AXLE HUB
(See page SA±10)
2. REMOVE LOWER BALL JOINT
(a) Using a

Page 3602 of 4592

TOYOTA CAMRY 1999  Service Repair Manual SA080±01
R08850
R08861
SST
SST SA±46
± SUSPENSION AND AXLEFRONT LOWER BALL JOINT
1997 Author: Date:
INSTALLATION
1. INSTALL LOWER BALL JOINT
(a) Install the lower ball joint and tighten the nut.

Page 3629 of 4592

TOYOTA CAMRY 1999  Service Repair Manual F08080
Front:
Rear:SA1DP±03
Z03382
± SUSPENSION AND AXLEFRONT WHEEL ALIGNMENT
SA±1
508 Author: Date:
FRONT WHEEL ALIGNMENT
INSPECTION
1. MEASURE VEHICLE HEIGHT
Vehicle height:
Tire sizeFront*1

Page 3631 of 4592

TOYOTA CAMRY 1999  Service Repair Manual SA3213
Front A
DB
C
F02245
F02246
SA0028
Front AB
A B
A: Inside
B: Outside
± SUSPENSION AND AXLEFRONT WHEEL ALIGNMENT
SA±3
510 Author: Date:
5. INSPECT TOE±IN
Toe±in:
Toe±in
(total)A + B: 0°