2014 BMW MOTORRAD R 1200 GS Руководство по эксплуатации (in Russian)

HKD

%
%



+
%
"/%%
 (
+
%  

%
+%
!



%&  \f %+* \f& % 

 

\f\f

!
\f
 %

"
H_ 0
%
%+
)%
\f "
0
%
%
)%
\f   
)%
   \f %
  
@%- 

  "
GHE
 
%%& 

+!
%%& \f\f
"
JK0\f

-%%
 \f!+%"
KH<% 


\b%& \f+\f
"
KHS<
 \b
\f& \f\f

% 
& \f %
\f "
GHKE
 
%%& \f\f

!
 

\fFGHKI"
ZJS 0\f
 
% 
& +
%& 
-  $%-"
8
 \b
' 



  


%
%* 
+
  %%
 
+
 " , %%
 

+\f 

(\f 
\f+* \f& 

%
%




+%
FHKI  

%
%
%
)%
\f  FH_I 
+!

" '
)\f 
+%
\f
\f \f 
%%
 
\b
 %

\f* \f& )

(

%  

  
+



!
\f \f 
  %$
 


" ;)

+
)% \f-
)
%& \f 
+)
%% 

 \b

\f

%
\b&  (\f+
 %
 \f
%
%"
Y\f $ 
\f%.
%

+
%
 



%

\f%
 %%
 

\f 

(\f+  (

%\b
 \b
(



%

\f%


%
 

\f 

(\f+ "
0.
.\b\b
,\f
%%


- \f\f
 
.%
\f   %%
 

+\f 

(\f  \f


+\f * \f %  JN` FA

+ %\f   \f % I \f

).-\f&  %- 
\f+%&- 

\f" , (\f
 +%- \f
%
%&- &

%-\f % 

)% \f-
)
%&"

:
7!
\b\b

4\b \f\f
,\f
 

% 

\f%
\f  \b
\f  


 

\f
\b
\f& 
\f
&%%\f

$
%\f 
%
 - 
%+\f 


%&  +%
)%
\f
" E

)
\f  \b%
 \f-
)
% 
)
\f
 %%
!


\f 
\f%.
%
 $
!


+"   )
%
\f*\b


)%
\f 
$+
" , \f& \f (   
\f\f 
   \b
\f

)+.
\f&  

\f 
\f

%&*\f  
\f%& %

+! \f) 
\f%
%
 &
^&
%& 

% *+\b
\f
!
-
"

5
7!
\b\b

\b %
\b
8.  \f
 " " " " " " " " " " " " " " " " " " 22
8.  \f " " " " " " " " " " " " " " " " " 2=
'
 \f
%
 " " " " " " " " " " " " " " " " " " " " " " 23
>
 
 
- 

*\b
+

 " " " " " " " " " " " " " " " " " " " " " " " " " " " " " " " " " 26
' 
 
- 

*\b+


 " " " " " " " " " " " " " " " " " " " " " " " " " " " " " " " 2:
9
%& 

 " " " " " " " " " " " " " 25
$
4
7\b
%
\b

$
21
7\b
%
\b

!6
  
\b
\f 
\f
&%% )%\f

HK
'
\f
&%% )%\f
F71I
$8 
\f 
& 
 F43I
(/
 \f
%& F:4I
*B
!
 %-
 

 F% %
 
%%
 \f

IF:?I
$
22
7\b
%
\b

$
2?
7\b
%
\b

!6
 \b
\b
B
!
 
+
%
!
\f) & %
)% F:2I
$,
$% @  F
\f
%
 \b\f *
+
I F2=1I
('

% \b
 &

%
 )
\f F22=I
*B
!
 \f


. %
!
. F:4I
#[

& 

F231I
-C
% @
%% %
+
 F% 
$%
+

 !

I
/
\f& \b F%
\f

 \fI
/C%
 
%&
-)*.
 )
\f F226I
[\b
 \f
-)*.
)
\f * F226I
,8 
\f 
& \f  !
F221I
'C%
 
%& \f !

F214I
1<&
%&  
&F 





IF2==I
8
% 
 &+
%
  
 F 

+



I F2=2I
/% \b
 &

+%
 )
\f  F223I
$
2=
7\b
%
\b

 \f
0 % % 

 %\f 
%
 F215I
$B

\f 

(\f+  
\f)%*
(; %\b
% 
+%& 
-  $%-
*; 
\f 
 %+!
#B
!
 \f
 \f+
%& 

& F52I
-'

-%
 F2=:I
$
23
7\b
%
\b